# Exercise 2.5

Complete above steps to enable this content

**1. Find:**

**Solution:**

### a

We use the basic concepts of decimal multiplication and division to solve the questions given.

(i) 0.4 ÷ 2

= 4/10 × 1/2

= 2/10

=

(ii) 0.35 ÷ 5

= 0.35 × 1/5

= 35/100 × 1/5

= 7/100

=

(iii) 2.48 ÷ 4

= 248/100 × 1/4

= 62/100

=

(iv) 65.4 ÷ 6

= 654/10 × 1/6

= 109/10

=

### b

(v) 651.2 ÷ 4

= 6512/10 × 1/4

= 1628/10

=

(vi) 14.49 ÷ 7

= 14.49 × 1/7

= 1449/100 × 1/7

= 1449/700

= 207/100

=

(vii) 3.96 ÷ 4

= 3.96 × 1/4

= 396/100 × 1/4

= 396/400

= 99/100

=

(viii) 0.80 ÷ 5

= 0.80 × 1/5

= 80/100 × 1/5

= 16/100

=

**2. Find:**

**Solution:**

### a

We use the basic concepts of decimal division to solve the given problems.

(i) 4.8 ÷ 10

= 48/10 × 1/10

= 48/100

=

(ii) 52.5 ÷ 10

= 525/10 × 1/10

= 525/100

=

(iii) 0.7 ÷ 10

= 7/10 × 1/10

= 7/100

=

(iv) 33.1 ÷ 10

= 331/10 × 1/10

= 331/100

=

### b

(v) 272.23 ÷ 10

= 27223/100 × 1/10

= 27223/1000

=

(vi) 0.56 ÷ 10

= 56/100 × 1/10

= 56/1000

=

(vii) 3.97 ÷10

= 397/100 × 1/10

= 397/1000

=

**3. Find:**

**Solution:**

### a

We use the basic concepts of decimal division to solve the given problems.

(i) 2.7 ÷ 100

= 27/10 × 1/100

= 27/1000

=

(ii) 0.3 ÷ 100

= 3/10 × 1/100

= 3/1000

=

(iii) 0.78 ÷ 100

= 78/100 × 1/100

= 78/10000

=

### b

(iv) 432.6 ÷ 100

= 4326/10 × 1/100

= 4326/1000

=

(v) 23.6 ÷ 100

= 236/10 × 1/100

= 236/1000

=

(vi) 98.53 ÷ 100

= 9853/100 × 1/100

= 9853/10000

=

**4. Find:**

**Solution:**

### a

We use the basic concepts of decimal division to solve the given problems.

(i) 7.9 ÷ 1000

= 79/10× 1/1000

= 79/10000

=

(ii) 26.3 ÷ 1000

= 26.3 × 1/1000

= 263/10 × 1/1000

= 263/10000

=

### b

(iii) 38.53 ÷ 1000

= 38.53 × 1/1000

= 3853/100 × 1/1000

= 3853/100000

=

(iv) 128.9 ÷ 1000

= 128.9 × 1/1000

= 1289/10 × 1/1000

= 1289/10000

=

(v) 0.5 ÷ 1000

= 0.5 × 1/1000

= 5/10 × 1/1000

= 5/10000

=

**5. Find:**

**Solution:**

### a

We use the basic concepts of decimal division to solve the given problems.

(i) 7 ÷ 3.5

= 7 × 1/3.5

= 7 × 10/35

= 70/35

= 2/1 =

(ii) 36 ÷ 0.2

= 36 × 1/0.2

= 36 × 10/2

= 360/2

=

(iii) 3.25 ÷ 0.5

= 3.25 × 1/0.5

= 3.25 × 10/5

= 3.25 × 2

=

(iv) 30.94 ÷ 0.7

= 3094/100 × 1/0.7

= 3094/100 × 10/7

= 3094/70

=

### a

(vi) 0.5 ÷ 0.25

= 5/10 × 1/0.25

= 5/10 × 100/25

= 50/25

=

(vii) 76.5 ÷ 0.15

= 76.5 × 1/0.15

= 7650/15

=

(viii) 37.8 ÷ 1.4

= 37.8 × 1/1.4

= 378/10 × 10/14

= 378/14

=

(ix) 2.73 ÷ 1.3

= 273/100 × 10/13

= 21/10

=

**6.A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How much distance will it cover in one litre of petrol?**

**Solution:**

We use basic multiplication and division of decimals to solve the problem given.

By using unitary method, we can simply divide 43.2 by 2.4 to get how much distance will the vehicle cover in 1 liter of petrol.

Distance covered in 2.4 litre of petrol =

Distance covered in 1 litre of petrol =

= 432/10 × 10/24

=

**Thus, it covers a distance of 18 km in 1 liter of petrol.**