# Enhanced Curriculum Support

**Sample question paper**

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This is a comprehensive educational resource designed to provide students with the tools and guidance necessary to excel. This support system is structured to cater to various aspects of learning, ensuring that students are well-prepared for academic challenges and practical applications of mathematical concepts. Some are the key benefits are mentioned below:

**Comprehensive Learning:** This holistic approach helps students gain a thorough understanding of the subject. Practical Application: The resources encourage students to apply mathematical concepts to real-life scenarios, enhancing their practical understanding and problem-solving skills.

**Critical Thinking and Reasoning:** Value-Based and HOTS questions promote critical thinking and reasoning abilities. These skills are crucial for students to tackle complex problems and make informed decisions.

**Exam Preparedness:** Sample Question Papers and NCERT Exemplar Solutions provide ample practice for exams. They help students familiarize themselves with the exam format and types of questions, reducing exam anxiety.

**Ethical and Moral Development:** Value-Based Questions integrate ethical and moral lessons into the learning process, helping in the overall development of students' character and social responsibility. By incorporating these diverse elements, Enhanced Curriculum Support aims to provide a robust and well-rounded knowledge, preparing students for both academic success and real-world challenges.

## Sample Questions

**Sample Question Paper:** These are designed to mimic actual exam papers, providing students with a practice platform to gauge their understanding and readiness. They cover a wide range of topics and question types that students might encounter. Regular practice with these papers helps in boosting confidence and improving exam performance.

**Quick Points:**

Practice for real exam scenarios.

Includes various types of questions.

Helps in time management.

Identifies areas of improvement.

**SecA**

**Round the number 23,487 to the nearest ten, hundred, and thousand**

**Sol**

**Solution:**

Nearest ten: 23,490

Nearest hundred: 23,500

Nearest thousand: 23,000

**SecB**

**Write the number names for**

**(a)765,490,786**

**(b)24,58,765**

**Sol**

**Solution:**

**(a)** Seven hundred sixty five million four hundred ninety thousand sevend hundred and eighty six

**(b)** Twenty four lakh fifty eight thousand seven hundred sixty five

**SecC**

**A store sold 785 bags in January, 956 bags in February, and 1,234 bags in March. What is the total number of bags sold in these three months?**

**Sol**

**Solution:** 4,800 - 2,650 =

**SecD**

**Write a number between 5,000 and 6,000 that is divisible by 5 and explain how you know it is divisible by 5**

**Sol**

**Solution:** 5,005; A number is divisible by 5 if it ends in 0 or 5.

**Value based questions**

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**Value-Based Questions:** They integrate moral and ethical values into the learning process, encouraging students to think beyond just academic knowledge. These questions aim to develop a student's character and social responsibility through mathematics. They connect mathematical concepts with everyday life and moral lessons.

**Quick Points:**

Promotes critical thinking.

Encourages ethical reasoning.

Relates mathematics to real-life scenarios.

Enhances decision-making skills.

**Problem 1**

**Situation:** A sports stadium has a seating capacity of 25,000. During a major event, 19,876 people attended.

**Questions:**

**(1)How many seats were left vacant during the event?**

**(2)Why is it important to have events that bring people together in large numbers?**

**Sol**

**Solutions**

**(1)** Calculating the number of vacant seats:

Vacant seats = 25,000−19,876=5,124 seats

**(2)** Importance of events that bring people together:

**Community Building:** Such events foster a sense of community and belonging.

**Cultural Exchange:** They allow for the exchange of ideas and cultures.

**Entertainment and Leisure:** They provide a source of entertainment and relaxation.

**Economic Benefits:** Large events can boost local economies through tourism and related activities.

**Problem 2**

**Situation:** Two factories produced 15,876 and 18,542 units of goods respectively in a month.

**Questions:**

**(1)By how many units did the second factory produce more than the first?**

**(2)Discuss the importance of fair competition between businesses.**

**Sol**

**Solutions**

**(1) Calculating the difference in production:**

Difference in production=18,542−15,876=2,666 units

**(2)Importance of fair competition:**

**Innovation and Improvement:** Fair competition encourages businesses to innovate and improve their products and services.

**Consumer Benefits:** It leads to better quality and more choices for consumers.

**Economic Growth:** Healthy competition can drive economic growth and job creation.

**Ethical Standards:** Fair competition promotes ethical business practices and prevents monopolies.

**Problem 3**

**Estimation and Rounding Off**

**Situation:** A school library plans to buy new books. The total cost of 48 science books is ₹19,472. Estimate the cost of each book by rounding off the total cost to the nearest thousand.

**Questions:**

**1. What is the estimated total cost and estimated cost per book?**

**2. Why is it important to budget and plan for expenses?**

**Sol**

**Solutions**

**Estimating the total cost and cost per book:**

Estimated total cost = ₹20,000

Estimated cost per book = ₹20,00048 ≈₹417 per book

Estimated cost per book=48₹20,000≈₹417 per book

**Importance of budgeting and planning for expenses:**

**Financial Management:** It helps in managing finances and avoiding overspending.

**Resource Allocation:** Ensures that resources are allocated efficiently.

**Achieving Goals:** Helps in setting and achieving financial goals.

**Preparedness:** Prepares individuals and organizations for unforeseen expenses.

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**HOTS (Higher Order Thinking Skills):** They require students to apply, analyze, synthesize, and evaluate information rather than just recall facts. These questions are designed to challenge students and stimulate intellectual growth. Engaging with HOTS questions helps students to develop a deeper understanding and prepares them for complex problem-solving.

**Quick Points:**

Develops advanced problem-solving skills.

Encourages deep understanding.

Fosters creativity and innovation.

Enhances analytical abilities.

**Q1**

**1.Write the smallest and the greatest 5-digit numbers using the digits 0,2,4,6,8 (Repetition of digits is not allowed).**

**Sol**

**Solution**

**Given digits are 0, 2, 4, 6, 8**

5 – digit greatest number = 86420;

5 – digit smallest number = 20468.

**Q2**

**2. Write the following numbers in ascending order. How many of them are even numbers? 63,854, 63,584, 65,348, 68,543, 64,835**

**Sol**

**Solution**

**The given numbers are 63,854, 63,584, 65,348, 68,543 and 64,835.**

**Q3**

**3.What is the successor of greatest 6-digit number?**

**Sol**

**Solution**

Greatest 6-digit number =

Successor of it = 999999 + 1 =

i. e., smallest 7-digit number.

Hence, the required successor = 10,00,000.

**Ncert exemplar solutions**

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**NCERT Exemplar Solutions:** They provide detailed answers and explanations to problems in NCERT textbooks, aiding students in understanding complex concepts. These solutions serve as a valuable resource for clarifying doubts and reinforcing learning. They are essential for thorough exam preparation and achieving academic excellence.

**Quick Points:**

Comprehensive solutions for NCERT problems.

Clarifies difficult concepts.

Useful for exam preparation.

Provides step-by-step explanations

**Answer Ncert exemplar questions**

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**Questions**

**1. In Indian System of Numeration, the number 58695376 is written as**

**2. The largest 4-digit number, using any one digit twice, from digits 5,9, 2 and 6 is**

**3. One million is equal to**

**4. Keeping the place of 6 in the number 6350947 same, the smallest number obtained by rearranging other digits is**

**5. The largest 5-digit number having three different digits is**

**6. The smallest 4-digit number having three different digits is**

**7. The largest number which always divides the sum of any pair of consecutive odd numbers is**

**8. The numbers 4578, 4587, 5478, 5487 are in descending order.**

**9. The largest six digit telephone number that can be formed by using digits 5, 3, 4, 7, 0, 8 only once is 875403.**

**10. The number 81652318 will be read as eighty one crore six lakh fifty two thousand three hundred eighteen.**

**11. The largest 4-digit number formed by the digits 6, 7, 0, 9 using each digit only once is 9760.**

**Sol**

**Solutions**

**1. Five crore, eighty six lakh, ninety five thousand, three hundred and seventy six.**

**2. 9965**

**3. 10 lakhs [10,00,000]**

**4. 6034579**

**5. 99987**

**6. 1002**

**7. 4**

**8. False**

**9. False**

**10. False**

**11. True**

**Case-Based Questions**

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**Case-Based Question:** They present real-life situations requiring students to apply their mathematical knowledge to solve problems, promoting practical understanding. These questions enhance the ability to connect theoretical knowledge with practical applications. They are instrumental in developing problem-solving skills relevant to real-world scenarios.

**Quick Points:**

Real-life application of concepts.

Encourages analytical thinking.

Enhances comprehension of practical problems.

Promotes interdisciplinary learning.

**Q1**

**Population processes are typically characterized by processes of birth and immigration, and of death, emigration and catastrophe, which correspond to the basic demographic processes and broad environmental effects to which a population is subject.**

The population of Telangana state in 2011 was 35193978 and the estimated population of the state in 2023 is 38157311

**Based on the above information, answer the following questions.**

**(i) Write the population of 2023 in words.**

**(ii) Write the place value of '1' in 35193978.**

**(iii) Write the population of 2011 and 2023 in expanded form.**

**Sol**

**Solutions**

**(i)** The population of 2023 in words is 3,81,57,311 Three croes eighty one lakh fifty seven thousand three hundred and eleven.

**(ii)** The place value of 1 in this number 3,51,93,978 is one lakh

**(iii)** 2011 = 2 x

2023 = 2 x

**Q2**

**Your classroom has a small library with 350 storybooks, 420 textbooks, and 230 reference books.**

**Based on the above information, answer the following questions.**

**1. What is the total number of books in the library?**

**2. If the storybooks are arranged in shelves with 25 books per shelf, how many shelves are needed?**

**3. How many more textbooks are there compared to reference books?**

**4. If you need to equally distribute all the books among 10 students, how many books will each student get?**

**5. What is the ratio of storybooks to the total number of books in the library?**

**Sol**

**Solutions**

Total books = 350 + 420 + 230 = 1000 books.

Shelves needed =

=350 25 shelves. Difference = 420-230 =

textbooks. Books per student =

=1000 10 books. Ratio =

=350 1000 (or 7 : 20).7 20

**Q3**

**You are planning a birthday party and you have 150 balloons, 200 candies, and 50 gift bags. You plan to put 3 balloons and 5 candies in each gift bag.**

**Based on the above information, answer the following questions.**

**1. How many balloons and candies will be used to fill all the gift bags?**

**2. How many balloons will be left after filling all the gift bags?**

**3. How many candies will be left after filling all the gift bags?**

**4. If you decide to put 10 candies in each gift bag instead, how many gift bags can you fill completely?**

**5. What is the total number of items (balloons, candies, and gift bags) you have for the party?**

**Sol**

**Solutions**

- Balloons used = 50bags x 3balloons = 150. (all balloons used)

Candies used = 50bags x 5candies = 250 candies.

Balloons left = balloons present-balloons needed=150 - 150 = 0.

Candies left = not enough candies as we have 200 but we need 250.

Gift bags =

=200 10 bags. Total items = 150 + 200 + 50 =

items.